Lower Secondary Number Theory Foundation

The Division Algorithm

Write whole-number division as divisor × quotient + remainder, then check that the remainder is valid.

Lesson focus

Write whole-number division as divisor × quotient + remainder, then check that the remainder is valid.

Read the worked example, then use the practice and quiz to check your understanding.

Start with a familiar division

Think about $137[[div]]12$. The answer is 11 remainder 5 because $12[[cdot]]11=132$ and there are 5 left over.

Write it as an equation: $137=12[[cdot]]11+5$.

Here 137 is the total, 12 is the divisor, 11 is the quotient, and 5 is the remainder.

The division algorithm is a compact way to write the same idea: $a=bq+r$. It means total = divisor × quotient + remainder.

Check that the remainder is valid

When the divisor is positive, the remainder must satisfy $0[[leq]] r < b$. In words: the remainder cannot be negative, and it must be smaller than the divisor.

Example: $137=12[[cdot]]11+5$ is valid because $0[[leq]]5<12$.

$137=12[[cdot]]10+17$ is arithmetically true, but 17 is not a valid remainder when dividing by 12. It is large enough to make another group of 12.

Before you leave

Write a complete mathematical sentence, not only a final number. Check whether your answer matches the condition in the question.

Practice Problems

Attempt each question before opening its answer.

Practice 1

When 245 is divided by 17, write the result in the form $17q+r$.

Show answer

$245=17[[cdot]]14+7$.

So $q=14$ and $r=7$. Check: $0[[leq]]7<17$.

Practice 2

If $n=11q+7$, what remainder does $n+15$ leave when divided by 11?

Show answer

$n+15=11q+22=11(q+2)$.

There is no amount left over, so the remainder is 0.

Interactive Quiz

Check one key idea before you move on.

1. When dividing by a positive number $b$, which remainder is valid?

$r=b$
$0[[leq]] r < b$
$r<0$